0=x^2-92x+360

Solution for 0=x^2-92x+360 equation:

0=x^2-92x+360

We move all terms to the left:

0-(x^2-92x+360)=0

We add all the numbers together, and all the variables

-(x^2-92x+360)=0

We get rid of parentheses

-x^2+92x-360=0

We add all the numbers together, and all the variables

-1x^2+92x-360=0

a = -1; b = 92; c = -360;
Δ = b2-4ac
Δ = 922-4·(-1)·(-360)
Δ = 7024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{7024}=\sqrt{16*439}=\sqrt{16}*\sqrt{439}=4\sqrt{439}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(92)-4\sqrt{439}}{2*-1}=\frac{-92-4\sqrt{439}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(92)+4\sqrt{439}}{2*-1}=\frac{-92+4\sqrt{439}}{-2}
$